Skip to main content

All Solution Code of CodeChef May Long Challenge 2021

competitve programming solution here...

solution code of Solubility problem number-1 of may long challenge codechef

Solubility Problem Solution Code: CodeChef

Solution Code

#include <bits/stdc++.h>
using namespace std;
#define int long long int
#define endl "\n"

int32_t main()
{
    int t;
    cin >> t;
    while (t--)
    {
        int p, x, y;
        cin >> p >> x >> y;
        int ans = 0;
        ans = x + (100 - p) * y;
        ans = ans * 10;
        cout << ans << endl;
    }
    return 0;
}

Comments

Popular posts from this blog

solution code of Modular Equation problem number-5 of may long challenge codechef

 Modular Equation Problem Code: CodeChef Solution Code #include <bits/stdc++.h> using   namespace   std ; #define   int   long   long   int #define   endl   " \n " int32_t   main () {      ios_base :: sync_with_stdio ( false );     cin. tie ( 0 );      int  t;cin >> t;      while (t -- )     {          int  n, m;cin >> n >> m;          int  count_of_pair  =   0 ;          vector < int >  modular_equation(n + 1 ,  1 );          for ( int  a  =   2 ;a <= n;a ++ )         {              int  x  =  m % a;             count_of_pair  +=  modular_equation [ x ] ;              for ( int  b  =  x;b <= n;b += a)             {                 modular_equation [ b ] ++ ;             }         }         cout << count_of_pair << endl ;     }      return   0 ; }

solution code of Tree House problem number-6 of may long challenge codechef

 Tree House Problem Solution Code: CodeChef Solution Code #pragma   GCC   optimize (" Ofast ", " unroll-loops ") #include   <bits/stdc++.h> using   namespace   std ; #define   int   long   long   int #define   double   long   double using   pii   =   pair < int ,  int >; template  < typename   T > using   Prior   =   std :: priority_queue < T ,  vector < T >,  greater < T >>; #define   X  first #define   Y  second #define   eb  emplace_back #define   ALL ( x )  begin (x),  end (x) #define   RALL ( x )  rbegin (x),  rend (x) #define   fastIO ()  ios_base ::sync_with_stdio, cin. tie ( 0 ) mt19937_64  rng( chrono :: steady_clock :: now (). time_since_epoch (). count ()); inline   int   getRand ( int   L ,  int   R ) {      if  ( L   >   R )          swap ( L ,  R );      return  ( int )(rng()  %  ( uint64_t )( R   -   L   +   1 )  +   L ); } template  < typename   T1 ,  typename   T2 > ostream   &operator <<( ostre

solution code of Tic Tac Toe problem number-4 of may long challenge codechef

 Tic Tac Toe Problem Solution Code:  CodeChef Solution Code #include <bits/stdc++.h> using   namespace   std ; #define   ll   long   long   int int   main () {      ll  t;     cin >> t;      while (t -- )     {          ll  cx  =   0 , co  = 0 , c_ =   0 ;          char  a[ 3 ][ 3 ];          for ( ll  i = 0 ;i < 3 ;i ++ )         {              for ( ll  j = 0 ;j < 3 ;j ++ )             {                 cin >> a[i][j];                  if (a[i][j] == 'X' )cx ++ ;                  if (a[i][j] == 'O' )co ++ ;                  if (a[i][j] == '_' )c_ ++ ;             }         }          ll  wx  =   0 , wo  =   0 ;          if (a[ 0 ][ 0 ]  ==   'X'   &&  a[ 1 ][ 0 ]  ==   'X'   &&  a[ 2 ][ 0 ]  ==   'X' )wx = 1 ;          if (a[ 0 ][ 1 ]  ==   'X'   &&  a[ 1 ][ 1 ]  ==   'X'   &&  a[ 2 ][ 1 ]  ==   'X' )wx = 1 ;          if (a[ 0 ][ 2 ]  ==   'X'   &